80 - Remove Duplicates from Sorted Array II

LCD驱动芯片——BL55072A驱动程序 初始化子程序: START 0x7C; I2C子地址 0xEA;ICSET,软件复位芯片 0xC0;MODSET,关显示 0xF0;BLKCTL,关闪烁 0xA3;DISCTL,80Hz Line inversion,High Power mode 0xE8;ICSET,清复位bit1 STOP 显示刷新子程序: START 0x7C;I2C子地址 0xF0;BLKCTL,关闪烁 0xA3;DISCTL,80Hz Line inversion,High Power mode 0xE8或0xEC;ICSE 阅读详情

Follow up for "Remove Duplicates":
What if duplicates are allowed at most twice?

For example,
Given sorted array nums = [1,1,1,2,2,3],

Your function should return length = 5, with the first five elements of nums being 1, 1, 2, 2 and 3. It doesn't matter what you leave beyond the new length.

Subscribe to see which companies asked this question

思路分析:

增加一个count计数。

class Solution
{
public:
	int removeDuplicates(vector<int>& nums) 
	{
		int n = nums.size();

		if (n == 0)
		{
			return 0;
		}

		int key = nums[0];
		int count = 0;
		int start = 0;

		for (int i = 0; i < n; i++)
		{
			if (key == nums[i])
			{
				count++;
			}
			else
			{
				for (int j = 0; j < min(2, count); j++)
				{
					nums[start++] = key;
				}

				key = nums[i];
				count = 1;
			}
		}

		for (int j = 0; j < min(2, count); j++)
		{
			nums[start++] = key;
		}
		return start;

	}
};


某二级支行网络的设计与实现——配置脚本(1) 【代码】某二级支行网络的设计与实现——配置脚本(1) 阅读详情

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