Reverse Words in a String 翻转一个字符串里的单词顺序 @LeetCode

最新推荐文章于 2022-11-23 17:07:59 发布

chiiis

最新推荐文章于 2022-11-23 17:07:59 发布

阅读量2.5k

点赞数

CC 4.0 BY-SA版权

分类专栏： Leetcode LeetCode专栏

本文链接：https://blog.youkuaiyun.com/fightforyourdream/article/details/38531289

Leetcode 同时被 2 个专栏收录

153 篇文章

订阅专栏

LeetCode专栏

148 篇文章

订阅专栏

本文介绍了一道LeetCode上的简单题目：按单词翻转字符串。通过使用栈来实现字符串中每个单词的逆序输出，并保留单词间的单个空格。文章提供了完整的Java代码示例。

摘要生成于 C知道，由 DeepSeek-R1 满血版支持，前往体验 >

LeetCode新题，但是比较简单，直接用栈即可

Given an input string, reverse the string word by word.

For example,
Given s = "the sky is blue",
return "blue is sky the".

click to show clarification.

Clarification:

What constitutes a word?
A sequence of non-space characters constitutes a word.
Could the input string contain leading or trailing spaces?
Yes. However, your reversed string should not contain leading or trailing spaces.
How about multiple spaces between two words?
Reduce them to a single space in the reversed string.

public class Solution {
    public String reverseWords(String s) {
        if(s.length() == 0) {
            return s;
        }
        Stack<String> stack = new Stack<String>();
        String[] ss = s.split("\\s+");
        for(String word : ss) {
            stack.push(word);
        }
        StringBuilder sb = new StringBuilder();
        while(!stack.isEmpty()) {
            sb.append(stack.pop()).append(" ");
        }
        return sb.toString().trim();
    }
}