leetcode--Shortest Word Distance

Given a list of words and two words word1 and word2, return the shortest distance between these two words in the list. 

For example, 
Assume that words = ["practice", "makes", "perfect", "coding", "makes"]. 

Given word1 = “coding”, word2 = “practice”, return 3. 

Given word1 = "makes", word2 = "coding", return 1. 

题意：给定一个数组和两个单词word1,word2,返回两者最近的距离

word1不等于word2,但是两者可能在数组中出现多次

分类：数组

解法1：遍历数组，当遍历到word1,word2，记录下位置，并且每次都计算最新的最小值

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1. public class Solution {  
2.     public int shortestDistance(String[] words, String word1, String word2) {  
3.         if (words == null) return -1;  
4.         int idx1 = -1, idx2 = -1;  
5.         int diff = words.length;  
6.         for (int i = 0; i < words.length; i++) {  
7.             if (words[i].equals(word1)) {  
8.                 idx1 = i;                  
9.             } else if (words[i].equals(word2)) {  
10.                 idx2 = i;                  
11.             }  
12.             if(idx1!=-1&&idx2!=-1){  
13.                 diff = Math.min(diff,Math.abs(idx1-idx2));  
14.             }  
15.         }  
16.         return diff;  
17.     }  
18. }  

原文链接http://blog.youkuaiyun.com/crazy__chen/article/details/47859737