hdu 5053 the Sum of Cube

最新推荐文章于 2023-02-22 09:19:21 发布

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本文介绍了一个简单的编程问题：计算指定区间内所有整数的立方和。通过使用C语言实现，文章提供了一种直接的方法来解决这个问题，并强调了使用long long类型以避免溢出的重要性。

**Problem Description
A range is given, the begin and the end are both integers. You should sum the cube of all the integers in the range.

Input
The first line of the input is T(1 <= T <= 1000), which stands for the number of test cases you need to solve.
Each case of input is a pair of integer A,B(0 < A <= B <= 10000),representing the range[A,B].

Output
For each test case, print a line “Case #t: ”(without quotes, t means the index of the test case) at the beginning. Then output the answer – sum the cube of all the integers in the range.

Sample Input
2
1 3
2 5

Sample Output
Case #1: 36
Case #2: 224
**
水题，没什么思路好说的。
翻译：t组样例，求出在a到b范围内所有数的立方和，按照题目格式输出
唯一坑的地方就是注意数据范围，记得用long long

#include<stdio.h>
#include<math.h>
#include<stdlib.h>

int main()
{
    int t,a,b,i,j;
    long long sum;
    scanf("%d",&t);
    for( i = 1; i <= t; i ++)
    {
        scanf("%d%d",&a,&b);
        sum = 0;
        for( j = a; j <= b; j ++)
        {

            sum += pow(j,3);
        }
        printf("Case #%d: %lld\n",i,sum);
    }
    return 0;
}