349.intersection-of-two-arrays

最新推荐文章于 2020-11-02 09:46:28 发布
原创 最新推荐文章于 2020-11-02 09:46:28 发布 · 262 阅读 · 0 ·
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本文介绍了一个计算两个数组交集的方法，通过将第一个数组存入字典，并遍历第二个数组检查是否存在相同元素，若存在则加入结果列表并移除字典中的对应项。

给定两个数组，写一个函数来计算它们的交集。

例子:

 给定 num1= [1, 2, 2, 1], nums2 = [2, 2], 返回 [2].

提示:

  • 每个在结果中的元素必定是唯一的。
  • 我们可以不考虑输出结果的顺序。

解题思路：

    遍历第一个数组，并存到一个集合中去，然后再遍历第二个数组，如果第二个数组中存在集合中的元素，则将其放入ans中，并删除集合中的这个元素。

解题代码：

    

        d={}
        ans=[]
        for num in nums1:
            d[num]=d.get(num,1)
        for num in nums2:
            if num in d:
                ans.append(num)
                del d[num]
        return ans

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