java中浮点数运算中0作除数并不会出现异常,而是:
正数除以0得正无穷,负数除以0得负无穷,0除以0得NaN
同样情况若是整形数运算则会抛出异常
测试用例:
package mytest;
public class DivideTest {
private void testInt(int dividend, int divisor) {
try {
System.out.println("testInt: " + dividend + "/" + divisor + " = "
+ dividend / divisor);
} catch (RuntimeException e) {
System.out.println("testInt exception:" + e.getMessage());
}
}
private void testLong(long dividend, long divisor) {
try {
System.out.println("testLong: " + dividend + "/" + divisor + " = "
+ dividend / divisor);
} catch (RuntimeException e) {
System.out.println("testLong exception:" + e.getMessage());
}
}
private void testDouble(double dividend, double divisor) {
try {
System.out.println("testDouble: " + dividend + "/" + divisor
+ " = " + dividend / divisor);
} catch (RuntimeException e) {
System.out.println("testDouble exception:" + e.getMessage());
}
}
private void testFloat(float dividend, float divisor) {
try {
System.out.println("testFloat: " + dividend + "/" + divisor + " = "
+ dividend / divisor);
} catch (RuntimeException e) {
System.out.println("testFloat exception:" + e.getMessage());
}
}
public static void main(String[] args) {
DivideTest dt = new DivideTest();
// 整数
dt.testInt(0, 0);
dt.testInt(1, 0);
dt.testInt(-1, 0);
System.out.println();
// 长整形
dt.testLong(0, 0);
dt.testLong(1, 0);
dt.testLong(-1, 0);
System.out.println();
// 浮点
dt.testFloat(0, 0);
dt.testFloat(1, 0);
dt.testFloat(-1, 0);
System.out.println();
// 双精度
dt.testDouble(0, 0);
dt.testDouble(1, 0);
dt.testDouble(-1, 0);
}
}
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