PAT TEST 甲级1001. A+B Format (20)_输入整数a,b,输出a与b的和，a大于-1000000b<1000000-优快云博客

本文介绍了一个简单的程序，该程序实现了两个整数的加法运算，并将结果以标准格式输出，即每三位数字用逗号分隔。文章通过具体的示例展示了如何读取输入、计算和格式化输出结果。

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题目：

Calculate a + b and output the sum in standard format -- that is, the digits must be separated into groups of three by commas (unless there are less than four digits).

Input

Each input file contains one test case. Each case contains a pair of integers a and b where -1000000 <= a, b <= 1000000. The numbers are separated by a space.

Output

For each test case, you should output the sum of a and b in one line. The sum must be written in the standard format.

Sample Input

-1000000 9

Sample Output

-999,991

要点：A,B两个数相加，输出结果每3位分开

#include 
#include 
#include 

using namespace std;

string calculer(int a,int b)
{
  int sum = a + b;
  string result="";
  char temp;
  int count=0;
  bool mark=true;
  if ( sum < 0 )
  {
    sum = -sum;
    mark = false;
  }
  if(sum==0)
  {
    result="0";
  }else
  {
    while (sum/10>0)
    {
      temp=sum%10+'0';
      sum=sum/10;
      count++;
      if (count==4)
      {
        result=","+result;
       result=temp+result;
        count=count-3;
      }else result=temp+result;
    
    }
    if (sum%10!=0)
    {
      count++;
      temp=sum%10+'0';
      if (count==4)
      {
        result=","+result;
       result=temp+result;
      }else result=temp+result;
    }
    if(mark==false)
    {
      result="-"+result;
    }
  }
  return result;
}

int main()
{
  int a,b;
  string sum;
  cin >> a;
  cin >> b;
  if (((a>1000000) || (a<-1000000))||((b>1000000) || (b<-1000000)))
  {
    cout<<"error input";
  }else
  {
    sum=calculer(a,b);
    cout << sum <