Perl Puzzles Key(standard)

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Perl Puzzles Key

This is the key for the Perl puzzles. Corrections welcome.

Answers

  1. credit for noting that the two foo's are unrelated.

  2. a b

  3. c and 3

  4. $a is set to the eight character string consisting of foo='\' followed by a newline. $b is set to the eight character string $c='\'\n.

  5. credit for noting that empty line will be printed for empty lines and those consisting solely of the character 0 (zero).

  6. credit for noting that one outcome is that the Perl interpreter may crash if foo doesn't give consistent answers.

    The crash possibility was the documented behavior prior to 5.005, but apparently has been at least partially addressed in 5.005. The man page perl5005delta(1) describes sort as now "resistant to inconsistent comparison functions". Strangely, it doesn't describe it as "immune", so this bug may still exist in some form. (Thanks to AP for pointing this out.)

  7. It sets the initial index of arrays.

  8. $x is set to the number 6. $y is set to the string sort.

  9. prints 36

  10. nothing, it's a syntax error. extra credit for noting that a fix is $mt = (stat($file))[8];

  11. credit for noting that it depends on whether @foo exists, and if it does, depends on Perl's complex algorithm or "guess". major extra credit if you actually know the algorithm.

  12. credit for noting that it depends on whether somefunc() is evaluated in a list or scalar context.

  13. credit for noting that it might call handler immediately, depending on how handler is currently defined.

  14. credit for noting that it depends on whether x is currently defined as a sub, whether it was defined with a prototype and which prototype was used.

  15. It reads all lines of the standard input and replaces the second element of @foo with the first line read, discarding the rest of the lines read.

  16. credit for noting that the last doesn't exit the current do/while loop, but rather will exit an enclosing loop (if present) or cause an error.

  17. credit for noting that "exists" will be printed if the key merely exists, whereas the key must have a defined value in the hash in order for "defined" to be printed.

  18. It'll read the first ten lines and never print anything (unless $_ has been defined elsewhere).

  19. It will assign to $f string fooa if a file with that name exists in the current directory, or else it will assign string foob if a file with that name exists in the current directory, or else it will assign string foor if a file with that name exists in the current directory, or else it will assign the empty string.

  20. foo-11-1 or 1-1foo-1

  21. a floating point value corresponding to zero minus the square root of two.

  22. This was supposed to show you how the left "0" would get interpreted as a string and the right "0" interpreted as a number, but perl 5.8.0 (at least) seems to interpret both as numbers, in apparent contradiction to the perlop man page. Major extra credit if you knew that the documentation and implementation of this feature is out of sync.

    [The answer was supposed to be "credit for noting that the second expression is a number whose binary representation is all ones (the one's complement of zero, etc.), and for noting that the first expression is a one-character string where the ASCII value for the character is the ASCII value for the zero character with its bits flipped."]

    (Thanks to Bob Miller for help with this.)

    (The code given in the question doesn't actually do what I thought it did. I actually don't understand what it's doing. If you know, I'd love to hear an explanation.)

  23. 55 5 5

  24. credit for noting that length & $print_blanks fails and is not equivalent to, say, length() & $print_blanks.

  25. It prints the first line only.

  26. It sets $sos to the empty string.


© 2001 Mike Coleman
<!-- Created: Fri Jun 1 21:36:25 CDT 2001 --><!-- hhmts start -->Last modified: Fri Jun 13 23:43:38 CDT 2003 <!-- hhmts end -->
资源下载链接为: https://pan.quark.cn/s/9e7ef05254f8 行列式是线性代数的核心概念,在求解线性方程组、分析矩阵特性以及几何计算中都极为关键。本教程将讲解如何用C++实现行列式的计算,重点在于如何输出分数形式的结果。 行列式定义如下:对于n阶方阵A=(a_ij),其行列式由主对角线元素的乘积,按行或列的奇偶性赋予正负号后求和得到,记作det(A)。例如,2×2矩阵的行列式为det(A)=a11×a22-a12×a21,而更高阶矩阵的行列式可通过Laplace展开或Sarrus规则递归计算。 在C++中实现行列式计算时,首先需定义矩阵类或结构体,用二维数组存储矩阵元素,并实现初始化、加法、乘法、转置等操作。为支持分数形式输出,需引入分数类,包含分子和分母两个整数,并提供与整数、浮点数的转换以及加、减、乘、除等运算。C++中可借助std::pair表示分数,或自定义结构体并重载运算符。 计算行列式的函数实现上,3×3及以下矩阵可直接按定义计算,更大矩阵可采用Laplace展开或高斯 - 约旦消元法。Laplace展开是沿某行或列展开,将矩阵分解为多个小矩阵的行列式乘积,再递归计算。在处理分数输出时,需注意避免无限循环和除零错误,如在分数运算前先约简,确保分子分母互质,且所有计算基于整数进行,最后再转为浮点数,以避免浮点数误差。 为提升代码可读性和可维护性,建议采用面向对象编程,将矩阵类和分数类封装,每个类有明确功能和接口,便于后续扩展如矩阵求逆、计算特征值等功能。 总结C++实现行列式计算的关键步骤:一是定义矩阵类和分数类;二是实现矩阵基本操作;三是设计行列式计算函数;四是用分数类处理精确计算;五是编写测试用例验证程序正确性。通过这些步骤,可构建一个高效准确的行列式计算程序,支持分数形式计算,为C++编程和线性代数应用奠定基础。
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