</pre><pre name="code" class="python">import smtplib
from email.mime.text import MIMEText
mailto_list=['XXXXX@qq.com']
mail_host="smtp.gmail.com" #设置服务器
mail_user="XXXXX" #用户名
mail_pass="XXXXX" #口令
mail_postfix="gmail.com" #发件箱的后缀
def send_mail(to_list,sub,content):
me="hello"+"<"+mail_user+"@"+mail_postfix+">"
msg = MIMEText(content,_subtype='plain',_charset='gb2312')
msg['Subject'] = sub
msg['From'] = me
msg['To'] = ";".join(to_list)
try:
server = smtplib.SMTP()
server.connect(mail_host)
server.login(mail_user,mail_pass)
server.sendmail(me, to_list, msg.as_string())
server.close()
return True
except Exception as e:
print(str(e))
return False
def getMessage(pathOfMessageTXT):
messageFile = open(pathOfMessageTXT,'w')
titleOfTheMessage = messageFile.readline()
contentOfTheMessage = messageFile.read(77777)
return (titleOfTheMessage,contentOfTheMessage)
if __name__ == '__main__':
(titleOfTheMessage,contentOfTheMessage) = getMessage('Message.txt')
if send_mail(mailto_list,titleOfTheMessage,contentOfTheMessage):
print("发送成功")
else:
print("发送失败")
python3实现简单的邮件自动发送
最新推荐文章于 2024-04-02 07:00:00 发布