可以使用Java自带的JAXB库来将POJO转化成符合XML格式的字符串。
首先，需要在POJO类上添加JAXB注解，例如：
```java
@XmlRootElement
public class User {
private String name;
private int age;
public User() {}
public User(String name, int age) {
this
.name = name;
this
.age = age;
}
@XmlElement
public String getName() {
return name;
}
public void setName(String name) {
this
.name = name;
}
@XmlElement
public int getAge() {
return age;
}
public void setAge(int age) {
this
.age = age;
}
}
```
然后，可以使用JAXBContext和Marshaller将POJO转化成XML格式的字符串：
```java
public static String convertToXml(Object obj) throws JAXBException {
JAXBContext context = JAXBContext
.newInstance(obj
.getClass());
Marshaller marshaller = context
.createMarshaller();
marshaller
.setProperty(Marshaller
.JAXB_FORMATTED_OUTPUT, true);
StringWriter writer = new StringWriter();
marshaller
.marshal(obj, writer);
return writer
.toString();
}
```
调用方式如下：
```java
User user = new User("Tom", 30);
String xml = convertToXml(user);
System
.out
.println(xml);
```
输出结果如下：
```xml
<?xml version="1
.0" encoding="UTF-8" standalone="yes"?>
<user>
<age>30</age>
<name>Tom</name>
</user>
```
注意：需要添加以下依赖：
```xml
<dependency>
<groupId>javax
.xml
.bind</groupId>
<artifactId>jaxb-api</artifactId>
<version>2
.3
.1</version>
</dependency>
<dependency>
<groupId>com
.sun
.xml
.bind</groupId>
<artifactId>jaxb-core</artifactId>
<version>2
.3
.0
.1</version>
</dependency>
<dependency>
<groupId>com
.sun
.xml
.bind</groupId>
<artifactId>jaxb-impl</artifactId>
<version>2
.3
.1</version>
</dependency>
```
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