考虑优先级问题,才两个运算符,可以的
#include<stdio.h>
#include<string.h>
int main(){
int a,b,c,T,i,j,k,sum;
char ss1[10],ss2[10];
scanf("%d",&T);
while(T--){
scanf("%d%s%d%s%d",&a,ss1,&b,ss2,&c);
sum=0;
if((ss1[0]=='+'||ss1[0]=='-')&&(ss2[0]=='*'||ss2[0]=='/'||ss2[0]=='%')){
if(ss2[0]=='*') sum=b*c;
else if(ss2[0]=='/') sum=b/c;
else if(ss2[0]=='%') sum=b%c;
else if(ss2[0]=='+') sum=b+c;
else if(ss2[0]=='-') sum=b-c;
if(ss1[0]=='+') sum+=a;
else if(ss1[0]=='-') sum=a-sum;
}
if((ss1[0]=='+'||ss1[0]=='-')&&(ss2[0]=='+'||ss2[0]=='-')){
if(ss1[0]=='+') sum=a+b;
else if(ss1[0]=='-') sum=a-b;
if(ss2[0]=='+') sum+=c;
else sum-=c;
}
if((ss1[0]=='*'||ss1[0]=='/'||ss1[0]=='%')&&(ss2[0]=='*'||ss2[0]=='/'||ss2[0]=='%'||ss2[0]=='+'||ss2[0]=='-')){
if(ss1[0]=='*') sum=a*b;
else if(ss1[0]=='/') sum=a/b;
else if(ss1[0]=='%') sum=a%b;
if(ss2[0]=='*') sum=sum*c;
else if(ss2[0]=='/') sum=sum/c;
else if(ss2[0]=='%') sum=sum%c;
else if(ss2[0]=='+') sum+=c;
else if(ss2[0]=='-') sum-=c;
}
printf("%d\n",sum);
}
}