题目地址:http://acm.hdu.edu.cn/showproblem.php?pid=4450
题目描述:
Draw Something
Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)
Total Submission(s): 582 Accepted Submission(s): 500
Problem Description
Wangpeng is good at drawing. Now he wants to say numbers like “521” to his girlfriend through the game draw something.
Wangpeng can’t write the digit directly. So he comes up a way that drawing several squares and the total area of squares is the number he wants to say.
Input all the square Wangpeng draws, what’s the number in the picture?
Wangpeng can’t write the digit directly. So he comes up a way that drawing several squares and the total area of squares is the number he wants to say.
Input all the square Wangpeng draws, what’s the number in the picture?
Input
There are multiple test cases.
For each case, the first line contains one integer N(1≤N≤100) indicating the number of squares.
Second line contains N integers ai(1≤ai≤100)represent the side length of each square. No squares will overlap.
Input ends with N = 0.
For each case, the first line contains one integer N(1≤N≤100) indicating the number of squares.
Second line contains N integers ai(1≤ai≤100)represent the side length of each square. No squares will overlap.
Input ends with N = 0.
Output
For each case, output the total area in one line.
Sample Input
4 1 2 3 4 3 3 3 3 0
Sample Output
30 27
题意:求平方的和。
代码:
/*
Draw Something
*/
#include<stdio.h>
#include<stdlib.h>
__int64 Sum=0;
__int64 Num=0;
int N=0;
int main()
{
while(scanf("%d",&N)!=EOF&&N>0)
{
Sum=0;
while(N--)
{
scanf("%I64d",&Num);
Sum+=Num*Num;
}
printf("%I64d\n",Sum);
}
return(0);
}
本文介绍了一道编程题——通过计算多个正方形面积之和来传达特定信息。输入为不同正方形边长,输出为总面积。文章提供了完整的C语言实现代码。
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