Oulipo (KMP)

本文介绍了一种用于字符串匹配的高效算法——KMP算法,并通过一个具体的编程实例详细展示了该算法的工作原理及实现过程。KMP算法能够快速找到给定模式串在目标串中出现的所有位置,适用于大量文本数据的搜索任务。

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题目链接:https://vjudge.net/contest/248066#problem/B

参考链接:https://blog.youkuaiyun.com/qq_28175337/article/details/47336777

Oulipo

 

The French author Georges Perec (1936–1982) once wrote a book, La disparition, without the letter 'e'. He was a member of the Oulipo group. A quote from the book: 

Tout avait Pair normal, mais tout s’affirmait faux. Tout avait Fair normal, d’abord, puis surgissait l’inhumain, l’affolant. Il aurait voulu savoir où s’articulait l’association qui l’unissait au roman : stir son tapis, assaillant à tout instant son imagination, l’intuition d’un tabou, la vision d’un mal obscur, d’un quoi vacant, d’un non-dit : la vision, l’avision d’un oubli commandant tout, où s’abolissait la raison : tout avait l’air normal mais… 

Perec would probably have scored high (or rather, low) in the following contest. People are asked to write a perhaps even meaningful text on some subject with as few occurrences of a given “word” as possible. Our task is to provide the jury with a program that counts these occurrences, in order to obtain a ranking of the competitors. These competitors often write very long texts with nonsense meaning; a sequence of 500,000 consecutive 'T's is not unusual. And they never use spaces. 

So we want to quickly find out how often a word, i.e., a given string, occurs in a text. More formally: given the alphabet {'A', 'B', 'C', …, 'Z'} and two finite strings over that alphabet, a word W and a text T, count the number of occurrences of W in T. All the consecutive characters of W must exactly match consecutive characters of T. Occurrences may overlap. 
 

Input

The first line of the input file contains a single number: the number of test cases to follow. Each test case has the following format: 

One line with the word W, a string over {'A', 'B', 'C', …, 'Z'}, with 1 ≤ |W| ≤ 10,000 (here |W| denotes the length of the string W). 
One line with the text T, a string over {'A', 'B', 'C', …, 'Z'}, with |W| ≤ |T| ≤ 1,000,000. 

Output

For every test case in the input file, the output should contain a single number, on a single line: the number of occurrences of the word W in the text T. 
 

Sample Input

3
BAPC
BAPC
AZA
AZAZAZA
VERDI
AVERDXIVYERDIAN

Sample Output

1
3
0

next[i]记录的是 i 之前的(不包括 i )一列字符串的最大的最大的前后缀的位置;

举个栗子:

lens1  =  5

 0   1    2   3    4    5   6       下标

 A   B   C   A    B    D           字符串

-1   0   0    0    1    2    0       next 数组

如果与  A  B  C  A  B  A  B  C  A  B   D  比较

#include<cstdio>
#include<cstring>
#include<iostream>
using namespace std;
const int MAXN=1000005;
char s1[MAXN];
char s2[MAXN];
int next[MAXN];

int lens1,lens2;

void getnext(){

    int j=-1;
    int i=0;
    next[0]=-1;
    while(i<lens1){
        if(j==-1 || s1[i]==s1[j]){
            i++;
            j++;
            next[i]=j;
        }else{
            j=next[j];
        }
    }
}

int kmp(){
    int ans=0;
    int i=0;
    int j=0;
    while(i<lens2){
        cout<<i<<' '<<j<<endl;
        if(j==-1 ||s1[j]==s2[i]){
            i++;
            j++;
            if(j==lens1){
                ans++;
            }
        }else{
            j=next[j];
        }
    }
    return ans;
}

int main(){

    int t;
    cin>>t;
    while(t--){
        scanf("%s",s1);
        scanf("%s",s2);
        lens1=strlen(s1);
        lens2=strlen(s2);

        getnext();

//        for(int i=0;i<=lens1;i++){
//            cout<<next[i]<<' ';
//        }

        cout<<endl;
        cout<<kmp()<<endl;
    }
    return 0;
}

 

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