Python 正则表达式提取URL中的Path

正则表达式：
(?xi)\A
# Skip over scheme and authority, if any
([a-z][a-z0-9+\-.]*:(//[^/?#]+)?)?
# Path
([a-z0-9\-._~%!$&'()*+,;=:@/]*)


Python代码：
import re

subject = 'http://www.regexcookbook.com/index.html'

reobj = re.compile(r'''(?xi)\A
# Skip over scheme and authority, if any
([a-z][a-z0-9+\-.]*:(//[^/?#]+)?)?
# Path
([a-z0-9\-._~%!$&'()*+,;=:@/]*)''')


match = reobj.search(subject)
if match:
    print match.group(3)