key: use two stack s1,s2
/**
* Definition for binary tree
* struct TreeNode {
* int val;
* TreeNode *left;
* TreeNode *right;
* TreeNode(int x) : val(x), left(NULL), right(NULL) {}
* };
*/
class Solution {
public:
vector<vector<int> > zigzagLevelOrder(TreeNode *root) {
vector<vector<int>> res;
if(!root) return res;
stack<TreeNode*> s1,s2;
s1.push(root);
vector<int> temp;
while(!s1.empty() || !s2.empty()){
while(!s1.empty()){
TreeNode* cur = s1.top();
temp.push_back(cur->val);
s1.pop();
if(cur->left) s2.push(cur->left);
if(cur->right) s2.push(cur->right);
}
if(!temp.empty()) {
res.push_back(temp);
temp.clear();
}
while(!s2.empty()){
TreeNode* cur = s2.top();
temp.push_back(cur->val);
s2.pop();
if(cur->right) s1.push(cur->right);
if(cur->left) s1.push(cur->left);
}
if(!temp.empty()) {
res.push_back(temp);
temp.clear();
}
}
return res;
}
};