LeetCode.412.Fizz Buzz

leetcode:412.Fizz Buzz 题目 来源:力扣(LeetCode) 链接:https://leetcode-cn.com/problems/fizz-buzz 给你一个整数 n ,找出从 1 到 n 各个整数的 Fizz Buzz 表示,并用字符串数组 answer(下标从 1 开始)返回结果,其中: answer[i] == “FizzBuzz” 如果 i 同时是 3 和 5 的倍数。 answer[i] == “Fizz” 如果 i 是 3 的倍数。 answer[i] == “Buzz” 如果 i 是 5 的倍数。 answer 阅读详情

原题链接:Fizz Buzz

题目内容:Write a program that outputs the string representation of numbers from 1 to n.

But for multiples of three it should output “Fizz” instead of the number and for the multiples of five output “Buzz”. For numbers which are multiples of both three and five output “FizzBuzz”.

Example:

n = 15,
Return:
[
“1”,
“2”,
“Fizz”,
“4”,
“Buzz”,
“Fizz”,
“7”,
“8”,
“Fizz”,
“Buzz”,
“11”,
“Fizz”,
“13”,
“14”,
“FizzBuzz”
]


Python

class Solution(object):
    def fizzBuzz(self, n):
        """
        :type n: int
        :rtype: List[str]
        """
        def check_fb(num):
            if num%3 == 0:
                if num%5 == 0:
                    return "FizzBuzz"
                return "Fizz"
            if num%5 == 0:
                return "Buzz"
            return num
        return [str(check_fb(i)) for i in range(1, n+1)]
Leetcode 412. Fizz Buzz-蜂鸣器 Leetcode 412. Fizz Buzz-蜂鸣器;Given an integern, returna string arrayanswer(1-indexed) where: answer[i] == "FizzBuzz"ifiis divisible by3and5. answer[i] == "Fizz"ifiis divisible by3. answer[i] == "Buzz"ifiis divisible by5. answer[i] == i(a 阅读详情

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Leetcode 412. Fizz Buzz 题目 写一个程序,输出从 1 到 n 数字的字符串表示。 如果 n 是3的倍数,输出“Fizz”; 如果 n 是5的倍数,输出“Buzz”; 如果 n 同时是3和5的倍数,输出 “FizzBuzz”。 示例: n = 15, 返回: [ "1", "2", "Fizz", "4", "Buzz", "Fizz", "7", "8", "Fizz", "Buzz", "

weixin_43750513的博客 272

python-leetcode-412. Fizz Buzz

如果有更优化的需求,或者需要其他语言的实现,欢迎交流!

Lucy_wzw的博客 309

【LeetCode】412. Fizz Buzz

【LeetCode】412. Fizz Buzz 题目: Write a program that outputs the string representation of numbers from 1 to n. But for multiples of three it should output “Fizz” instead of the number and for the multipl...

A_Huiii的博客 171

【leetcode】412. Fizz Buzz

problem 412.Fizz Buzz solution: class Solution { public: vector<string> fizzBuzz(int n) { vector<string> res; for(int i=1; i<=n;++i) { ...

weixin_30379911的博客 75

力扣(leetcode)第412题Fizz Buzz(Python)

输出:[“1”,“2”,“Fizz”,“4”,“Buzz”,“Fizz”,“7”,“8”,“Fizz”,“Buzz”,“11”,“Fizz”,“13”,“14”,“FizzBuzz”]answer[i] == “FizzBuzz” 如果 i 同时是 3 和 5 的倍数。answer[i] == “Fizz” 如果 i 是 3 的倍数。answer[i] == “Buzz” 如果 i 是 5 的倍数。输出:[“1”,“2”,“Fizz”,“4”,“Buzz”]输出:[“1”,“2”,“Fizz”]

qq_58737789的博客 678

Java实现 LeetCode 412 Fizz Buzz

412. Fizz Buzz 写一个程序,输出从 1 到 n 数字的字符串表示。 如果 n 是3的倍数,输出“Fizz”; 如果 n 是5的倍数,输出“Buzz”; 3.如果 n 同时是3和5的倍数,输出 “FizzBuzz”。 示例: n = 15, 返回: [ "1", "2", "Fizz", "4", "Buzz", "Fizz"...

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