LeetCode.412.Fizz Buzz

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本文提供了一个简洁的Python实现方案来解决经典的编程问题FizzBuzz。该程序对于从1到指定数值的每个数字，输出其字符串形式，但对于3的倍数输出Fizz，5的倍数输出Buzz，同时为3和5的倍数则输出FizzBuzz。

原题链接：Fizz Buzz

题目内容：Write a program that outputs the string representation of numbers from 1 to n.

But for multiples of three it should output “Fizz” instead of the number and for the multiples of five output “Buzz”. For numbers which are multiples of both three and five output “FizzBuzz”.

Example:

n = 15,
Return:
[
“1”,
“2”,
“Fizz”,
“4”,
“Buzz”,
“Fizz”,
“7”,
“8”,
“Fizz”,
“Buzz”,
“11”,
“Fizz”,
“13”,
“14”,
“FizzBuzz”
]

Python

class Solution(object):
    def fizzBuzz(self, n):
        """
        :type n: int
        :rtype: List[str]
        """
        def check_fb(num):
            if num%3 == 0:
                if num%5 == 0:
                    return "FizzBuzz"
                return "Fizz"
            if num%5 == 0:
                return "Buzz"
            return num
        return [str(check_fb(i)) for i in range(1, n+1)]