Given two arrays, write a function to compute their intersection.
Example:
Given nums1 = [1, 2, 2, 1]
, nums2 = [2, 2]
, return
[2, 2]
.
Note:
- Each element in the result should appear as many times as it shows in both arrays.
- The result can be in any order.
class Solution {
public:
vector<int> intersect(vector<int>& nums1, vector<int>& nums2) {
if(nums1.size() == 0 || nums2.size() == 0) return {};
sort(nums1.begin(), nums1.end());
sort(nums2.begin(), nums2.end());
int i = 0, j = 0;
vector<int> res;
while(i < nums1.size() && j < nums2.size()) {
if(nums1[i] == nums2[j]) {
res.push_back(nums1[i]);
i++;
j++;
} else if(nums1[i] < nums2[j]) {
i++;
} else j++;
}
return res;
}
};