LeetCode 283. Move Zeroes

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Given an array nums, write a function to move all 0's to the end of it while maintaining the relative order of the non-zero elements.

For example, given nums = [0, 1, 0, 3, 12], after calling your function, nums should be [1, 3, 12, 0, 0].

Note:

You must do this in-place without making a copy of the array.
Minimize the total number of operations.

#include <vector>
#include <iostream>
using namespace std;

// if we dont care about the order.
void moveZeros(vector<int>& nums) {
    if(nums.size() == 0) return;
    int i = 0;
    int j = nums.size() - 1;
    while(i < j) {
        if(nums[i] == 0) {
            swap(nums[i], nums[j]);
            j--;
        } else {
            i++;
        }
    }
}

// if we want to keep the order.
void moveZerosII(vector<int>& nums) {
    if(nums.size() <= 1) return;
    int i = 0, j = 0;
    while(j < nums.size()) {
        if(nums[j] != 0) {
            nums[i++] = nums[j++];
        } else {
            j++;
        }
    }
    while(i < nums.size()) {
        nums[i++] = 0;
    }
}

int main(void) {
    vector<int> nums;
    nums.push_back(0);
    nums.push_back(1);
    nums.push_back(0);
    nums.push_back(3);
    nums.push_back(12);
<pre name="code" class="cpp">    // moveZeros(nums);

moveZerosII(nums); for(int i = 0; i < nums.size(); ++i) { cout << nums[i] << endl; } cout << endl;}