问题描述:
Given a binary tree, determine if it is a valid binary search tree (BST).
Assume a BST is defined as follows:
-The left subtree of a node contains only nodes with keys less than the node’s key.
-The right subtree of a node contains only nodes with keys greater than the node’s key.
-Both the left and right subtrees must also be binary search trees.
采用中序遍历,如果遍历过程严格服从从小到大,则在最后返回True,否则返回False
# Definition for a binary tree node
# class TreeNode:
# def __init__(self, x):
# self.val = x
# self.left = None
# self.right = None
class Solution:
# @param root, a tree node
# @return a boolean
def isValidBST(self, root):
def inOrder(root):
stack = []
p = root
minVal = None
while p or len(stack) > 0:
if p:
stack.append(p)
p = p.left
else:
p = stack.pop()
if None == minVal or minVal < p.val:
minVal = p.val
p = p.right
else:
return False
return True
return inOrder(root)
本文介绍了一种通过中序遍历来验证给定二叉树是否为有效二叉搜索树的方法。通过确保中序遍历结果严格递增,判断二叉树结构是否符合二叉搜索树的定义。
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