LeetCode 3. Longest Substring Without Repeating Characters (双指针扫描的典型例题)

本文详细解析了如何使用双指针法求解最长无重复子串的问题,通过具体的代码实现展示了算法的运行过程。文章包含多个示例,帮助读者理解算法原理。

摘要生成于 C知道 ,由 DeepSeek-R1 满血版支持, 前往体验 >

3. Longest Substring Without Repeating Characters

Medium

4883249FavoriteShare

Given a string, find the length of the longest substring without repeating characters.

Example 1:

Input: "abcabcbb"
Output: 3 
Explanation: The answer is "abc", with the length of 3. 

Example 2:

Input: "bbbbb"
Output: 1
Explanation: The answer is "b", with the length of 1.

Example 3:

Input: "pwwkew"
Output: 3
Explanation: The answer is "wke", with the length of 3. 
             Note that the answer must be a substring, "pwke" is a subsequence and not a substring.

题意:给你一个字符串,求最长不重复子串的长度。

题解:双指针扫描

 

class Solution {
public:
    int lengthOfLongestSubstring(string s) {
        map<char,int> mp;
        mp.clear();
        int begin = 0;
        int end = 0;
        int l = 0;
        int r = 0;
        int Max = 0;
        while(end < s.size()){
            mp[s[end]]++;
            if(mp[s[end]] > 1){
                while(begin <= end && mp[s[end]] > 1){
                    mp[s[begin]]--;
                    begin++;
                }
            }
            if((end - begin + 1) > Max){
                Max = (end - begin + 1);
                l = begin;
                r = end;
            }
            end++;
        }
        return Max;
    }
};

 

评论
添加红包

请填写红包祝福语或标题

红包个数最小为10个

红包金额最低5元

当前余额3.43前往充值 >
需支付:10.00
成就一亿技术人!
领取后你会自动成为博主和红包主的粉丝 规则
hope_wisdom
发出的红包
实付
使用余额支付
点击重新获取
扫码支付
钱包余额 0

抵扣说明:

1.余额是钱包充值的虚拟货币,按照1:1的比例进行支付金额的抵扣。
2.余额无法直接购买下载,可以购买VIP、付费专栏及课程。

余额充值