Sum Problem
Time Limit: 1000/500 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)
Total Submission(s): 500758 Accepted Submission(s): 127099
Problem Description
Hey, welcome to HDOJ(Hangzhou Dianzi University Online Judge).
In this problem, your task is to calculate SUM(n) = 1 + 2 + 3 + … + n.
Input
The input will consist of a series of integers n, one integer per line.
Output
For each case, output SUM(n) in one line, followed by a blank line. You may assume the result will be in the range of 32-bit signed integer.
Sample Input
1
100
Sample Output
1
5050
sum问题,注意下中间多一个空行就好
AC代码:
#include<iostream>
using namespace std;
int main(){
int x;
int i,sum=0;
while(cin>>x){
for(i=0;i<=x;i++)
sum+=i;
cout<<sum<<endl<<endl;
sum=0;
}
return 0;
}
更多查看我的个人博客:https://beatjerome.github.io
本文介绍了一个简单的HDOJ求和问题,任务是计算从1到n的所有整数之和。通过给出的示例代码,展示了如何使用C++解决这个问题,并提供了完整的代码实现。
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