el表达式获取url中文参数乱码

最新推荐文章于 2021-07-30 15:57:44 发布

singtorain

最新推荐文章于 2021-07-30 15:57:44 发布

阅读量1.8k

点赞数

分类专栏： java

本文链接：https://blog.youkuaiyun.com/gaohuimina/article/details/51889180

版权

java 专栏收录该内容

8 篇文章

订阅专栏

本文介绍了两种解决Tomcat服务器中URI编码问题的方法：一是通过修改server.xml中的Connector标签来设置正确的编码；二是通过自定义过滤器来对请求进行编码转换。

摘要生成于 C知道，由 DeepSeek-R1 满血版支持，前往体验 >

1.解决方法：改变tomcat文件server.xml标签connector的编码

2.解决方法：添加过滤器

转自：http://bbs.youkuaiyun.com/topics/250056412

import java.io.IOException;

import javax.servlet.Filter;
import javax.servlet.FilterChain;
import javax.servlet.FilterConfig;
import javax.servlet.ServletException;
import javax.servlet.ServletRequest;
import javax.servlet.ServletResponse;

public class MyFilter implements Filter {

public void destroy() {
// TODO Auto-generated method stub

}

public void doFilter(ServletRequest arg0, ServletResponse arg1,
FilterChain arg2) throws IOException, ServletException {
arg0.setCharacterEncoding("gbk");
arg2.doFilter(arg0, arg1);

}

public void init(FilterConfig arg0) throws ServletException {
// TODO Auto-generated method stub

}

}
XML：
<?xml version="1.0" encoding="UTF-8"?>
<web-app xmlns="http://java.sun.com/xml/ns/j2ee"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" version="2.4"
xsi:schemaLocation="http://java.sun.com/xml/ns/j2ee http://java.sun.com/xml/ns/j2ee/web-app_2_4.xsd">
<servlet>
<servlet-name>action</servlet-name>
<servlet-class>
org.apache.struts.action.ActionServlet
</servlet-class>
<init-param>
<param-name>config</param-name>
<param-value>/WEB-INF/struts-config.xml</param-value>
</init-param>

<load-on-startup>0</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>action</servlet-name>
<url-pattern>*.do</url-pattern>
</servlet-mapping>
<welcome-file-list>
<welcome-file>index.jsp</welcome-file>
</welcome-file-list>
<filter>
<filter-name>f</filter-name>
<filter-class>filter.MyFilter</filter-class>
</filter>
<filter-mapping>
<filter-name>f</filter-name>
<url-pattern>*</url-pattern>
</filter-mapping>
</web-app>