专注，努力，勤奋

#include #include #include long g_count = 0;long g_sum = 0;static const int g_s_Count = 10;CRITICAL_SECTION g_csThreadParamer;CRITICAL_SECTION g_csThreadCode;HANDLE g_threadEvent;

#include #include #include long g_count = 0;long g_sum = 0;static const int g_s_Count = 10;CRITICAL_SECTION g_csThreadParamer;CRITICAL_SECTION g_csThreadCode;HANDLE g_threadEvent;

#include #include #include long g_count = 0;long g_sum = 0;static const int g_s_Count = 10;CRITICAL_SECTION g_csThreadParamer;CRITICAL_SECTION g_csThreadCode;HANDLE g_threadEvent;

#include #include #include long g_count = 0;long g_sum = 0;static const int g_s_Count = 10;CRITICAL_SECTION g_csThreadParamer;CRITICAL_SECTION g_csThreadCode;HANDLE g_threadEvent;

先看例子代码：void CStudent::menuCallback(CCObject * pSender) { CStudent *temp = new CStudent("new student", 33); pthread_mutex_init(&mutex, NULL); pthread_create(&pidRun, NULL, run, temp);

#include#include#include#include pthread_mutex_t mutex = PTHREAD_MUTEX_INITIALIZER;/*初始化互斥锁*/pthread_cond_t cond = PTHREAD_COND_INITIALIZER;//init condvoid *thread1(void*);void *thread2(void

用下面一组函数（系统调用）来实现。int sem_init(sem_t *sem,int pshared,unsigned int value); int sem_destroy(sem_t *sem); int sem_wait(sem_t *sem); int sem_trywait(sem_t *sem); int sem_post(sem_t *sem); in

1、首先明确一点，对于单核CPU，任意一个时刻只有一个线程在运行。那么既然这样，多线程还有什么意义呢？ 举例来说，现在只有一个人，要做好几个任务。单线程就是，任务一个一个地做，必须做完一个任务后，再去做另一个任务。多线程就是一会做这个任务，一会做那个任务，每个任务做一会，不停的切换。显然，最后把所有的任务做完，多线程必定比单线程更耗费时间。为什么？因为，多线程要在不同的任务之间切换，切换肯定是要耗