Gorgeoustray

1令 c1=12,c2=1c_1=\frac{1}{2},c_2=1c1​=21​,c2​=1，因为 f(n),g(n)f(n),g(n)f(n),g(n) 均渐进非负，显然有c1(f(n)+g(n))≤max(f(n),g(n))≤c2(f(n)+g(n))c_1(f(n)+g(n))\leq max(f(n),g(n))\leq c_2(f(n)+g(n))c1​(f(n)+g(n))...

1{3, 9, 26, 38, 41, 49, 52, 57}{3, 26, 41, 52} {9, 38, 49, 57}{3, 41} {26, 52} {38, 57} {9, 49}{3} {41} {52} {26} {38} {57} {9} {49}2merge(A, p, q, r)m = q - q + 1n = r - qlet L[1..m] and R[...

1Θ(n3)\Theta(n^3)Θ(n3)2选择排序的伪码:for i = 1 to A.length - 1 min = i for j = i to A.length if A[j] < min min = j swap(a[i], a[min])最外层 for 的循环不变量：每次迭代开始时 AAA 的子数组 A[1…i−1]A[1\dots i-1]A[...

{31, 41, 59, 26, 41, 58}{31, 41, 59, 26, 41, 58}{31, 41, 59, 26, 41, 58}{26, 31, 41, 59, 41, 58}{26, 31, 41, 41, 59, 58}{26, 31, 41, 41, 58, 59}for j = 2 to A.length key = A[j] i = j - 1...

网页广告投放；即求不等式的正整数解：8n2<64n lg n2≤n≤438n^2<64n\ lg\ n\\2\le n\le438n2<64n lg n2≤n≤43根据以下的 C++ 代码，答案为 15#include <iostream>#include <cmath>using namespa...

Sorting: Search engines need to sort the searching results.Computing a convex hull: computing the minimum diameters of a set of points on a plane.Coding efficiency, reading efficiency.Array.Stren...