Description
You are given two non-empty linked lists representing two non-negative integers. The digits are stored in reverse order and each of their nodes contain a single digit. Add the two numbers and return it as a linked list.
You may assume the two numbers do not contain any leading zero, except the number 0 itself.
给出了两个非空链表,表示两个非负整数。数字以倒序存储,每个节点都包含一个数字。将两个整数相加并返回相加后的链表。
解:
- 两个链表相加的值加上进位为当前值,当前值与10的余数作为当前节点的值,同时更新进位。直到两个链表均遍历完且无进位。
java代码:
public class Solution {
public ListNode addTwoNumbers(ListNode l1, ListNode l2) {
ListNode head = new ListNode(0);
ListNode prev = head;
int count = 0;
while (l1 != null || l2 != null || count != 0){
ListNode now = new ListNode(0);
int sum = (l1 == null ? 0 : l1.val) + (l2 == null ? 0 : l2.val) + count;
now.val = sum % 10;
count = sum / 10;
prev.next = now;
prev = now;
if (l1 != null) l1 = l1.next;
if (l2 != null) l2 = l2.next;
}
return head.next;
}
}