myeclipse 6.5 blue 注册码

本文介绍了一种用于生成软件序列号的算法实现。该算法基于用户的ID、版本号及许可证编号等信息,通过日期操作、格式化数字及字符串拼接等步骤生成序列号。此外,还实现了序列号的校验码计算及字符转换方法。

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package com.kk.test;
import java.text.DecimalFormat;

import java.text.NumberFormat;

import java.text.SimpleDateFormat;

import java.util.Calendar;

public class GetID {
public static final void main(String[] args) {

String id = "kk";///"改为你的注册ID";

String num = "333";//"改为 1-999 的整数";

System.out.println(getSerial(id, "100", num, false));

}

public static String getSerial(String userId, String version,

String licenseNum, boolean selected) {

Calendar cal = Calendar.getInstance();

cal.add(1, 3);

cal.add(6, -1);

NumberFormat nf = new DecimalFormat("000");

licenseNum = nf.format(Integer.valueOf(licenseNum));

String verTime = selected ? (new StringBuffer("-")).append(

(new SimpleDateFormat("yyMMdd")).format(cal.getTime())).append(

"0").toString() : "-1412310"; //2014年12月31日过期 可修改为自己的过期时间

String type = "YE3MB-";

String need = (new StringBuffer(String.valueOf(userId.substring(0, 1))))

.append(type).append(version).append(licenseNum)

.append(verTime).toString();

String dx = (new StringBuffer(String.valueOf(need)))

.append(

"Decompiling this copyrighted software is a violation of both your license agreement "+

"and the Digital Millenium Copyright Act of 1998 (http://www.loc.gov/copyright/legislation/dmca.pdf). "+

"Under section 1204 of the DMCA, penalties range up to a $500,000 fine or up to five years "+

"imprisonment for a first offense. Think about it; pay for a license, avoid prosecution, and feel "+

"better about yourself.") .append(userId).toString();

int suf = decode(dx);

String code = (new StringBuffer(String.valueOf(need))).append(

String.valueOf(suf)).toString();

return change(code);

}

private static int decode(String s) {

int i = 0;

char ac[] = s.toCharArray();

int j = 0;

for (int k = ac.length; j < k; j++)

i = 31 * i + ac[j];

return Math.abs(i);

}

private static String change(String s) {

byte abyte0[] = s.getBytes();

char ac[] = new char[s.length()];

int i = 0;

for (int k = abyte0.length; i < k; i++) {

int j = abyte0[i];

if (j >= 48 && j <= 57)

j = ((j - 48) + 5) % 10 + 48;

else if (j >= 65 && j <= 90)

j = ((j - 65) + 13) % 26 + 65;

else if (j >= 97 && j <= 122)

j = ((j - 97) + 13) % 26 + 97;

ac[i] = (char) j;

}

return String.valueOf(ac);

}


}
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