Given a sorted linked list, delete all duplicates such that each element appear only once.
For example,
Given 1->1->2
, return 1->2
.
Given 1->1->2->3->3
, return 1->2->3
.
思路:
算法没什么好说的,链表实现一个功能:遇到重复的元素删去。
代码实现:
/**
* Definition for singly-linked list.
* struct ListNode {
* int val;
* ListNode *next;
* ListNode(int x) : val(x), next(NULL) {}
* };
*/
class Solution {
public:
ListNode* deleteDuplicates(ListNode* head) {
ListNode *temp=head;;
if(!temp){
return head;
}
while(temp->next){
if(temp->val==temp->next->val){
temp->next=temp->next->next;
}
else{
temp=temp->next;
}
}
return head;
}
};