flqbestboy的专栏

//求n以内（不包括n）同时能被3和7整除的所有自然数之和的平方根s， //并作为函数值返回。例如若n为1000时，函数值应为：s=153.909064。 #include #include #include using namespace std; double f(int x) { double sum=0; for(int i=3;i<x;i++) { if(i%

#include using namespace std; int main() { int n; while(cin>>n) { int tmp,i=0,arr[101]; while(n>0) { tmp=n%16; arr[++i]=tmp; n/=16;

//给出年月日输出下一天的日期 #include using namespace std; const int num[13]={0,31,28,31,30,31,30,31,31,30,31,30,31}; bool check(int x)//判断是否是闰年 { if((x%4==0&&x%100!=0)||x%400==0) return true; return

#include using namespace std; int main() { string str[10]={"","shi","bai","qian","wan","shi wan","bai wan","qian wan","yi"}; string num[10]={"ling","yi","er","san","si","wu","liu","qi","ba","j