BASE64编码解码

最新推荐文章于 2022-06-25 21:13:29 发布

原创最新推荐文章于 2022-06-25 21:13:29 发布 · 446 阅读

CC 4.0 BY-SA版权

#include "stdafx.h"
#include <string.h>
const unsigned char _Base64Map[] = {
   'A','B','C','D','E','F','G','H','I','J','K','L','M','N','O','P'
   ,'Q','R','S','T','U','V','W','X','Y','Z','a','b','c','d','e','f'
   ,'g','h','i','j','k','l','m','n','o','p','q','r','s','t','u','v'
   ,'w','x','y','z','0','1','2','3','4','5','6','7','8','9','+','/'
   ,52, 53, 54, 55, 56, 57, 58, 59, 60, 61, 255, 255,255, 254, 255, 255
   , 255, 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14
   , 15, 16, 17, 18,19, 20, 21, 22, 23, 24, 25, 255, 255, 255, 255, 255
   ,255, 26, 27, 28, 29, 30, 31, 32, 33, 34, 35, 36, 37, 38, 39, 40
   , 41, 42, 43, 44, 45, 46, 47, 48,49, 50, 51 };
#define _BASE64_MAP (_Base64Map+16)
int Base64Encode(char *in, int len, char *out)
{
   char * pOut = out;
   while (len >= 3)
   {
       *pOut++ = _Base64Map[in[0] >> 2];
       *pOut++ = _Base64Map[((in[0] & 3) << 4) + (in[1] >> 4)];
       *pOut++ = _Base64Map[((in[1] & 0xf) << 2) + (in[2] >> 6)];
       *pOut++ = _Base64Map[in[2] & 0x3f];
       len -= 3;
       in += 3;
   }
   if (len)
   {
       *pOut++ = _Base64Map[in[0] >> 2];
       if (len == 2)
       {
           *pOut++ = _Base64Map[((in[0] & 3) << 4) + (in[1] >> 4)];
           *pOut++ = _Base64Map[((in[1] & 0xf) << 2) ];
       }
       else
       {
           *pOut++ = _Base64Map[((in[0] & 3) << 4) ];
           *pOut++ = '=';
       }
       *pOut++ = '=';
   }
   *pOut = 0;
   return pOut - out;

}

int Base64Encode(char*RcYFF , char*EhIgQQ )
{
int VELBUUIJ =strlen(in);
return Base64Encode(RcYFF,VELBUUIJ,EhIgQQ );
}

int Base64Decode(char *in, char *out)
{
   int t, x, y, z;
   unsigned char c;
   int   g = 3;
   for (x = y = z = t = 0; in[x] != 0;) {
       char v = in[x++];
       if (v<33)
           continue;
       c = _BASE64_MAP[v];
       if (c == 255) return -1;
       if (c == 254) { c = 0; g--; }
       t = (t << 6) | c;
       if (++y == 4) {
           out[z++] = (unsigned char)((t >> 16) & 255);
           if (g > 1) out[z++] = (unsigned char)((t >> 8) & 255);
           if (g > 2) out[z++] = (unsigned char)(t & 255);
           y = t = 0;
       }
   }
   out[z] = 0;
   return z;

}