select * from effort e left outer join(select ue.effId id from user_effort ue where ue.userId=1) ut
on e.effId = ut.id where ut.id is null;
不用In 从A表中查出B表中没有的记录
最新推荐文章于 2022-03-12 23:30:24 发布
select * from effort e left outer join(select ue.effId id from user_effort ue where ue.userId=1) ut
on e.effId = ut.id where ut.id is null;