【牛客SQL】SQL2 查找入职员工时间排名倒数第三的员工所有信息

题目描述

示例1
输入：
drop table if exists  `employees` ; 
CREATE TABLE `employees` (
`emp_no` int(11) NOT NULL,
`birth_date` date NOT NULL,
`first_name` varchar(14) NOT NULL,
`last_name` varchar(16) NOT NULL,
`gender` char(1) NOT NULL,
`hire_date` date NOT NULL,
PRIMARY KEY (`emp_no`));
INSERT INTO employees VALUES(10001,'1953-09-02','Georgi','Facello','M','1986-06-26');
INSERT INTO employees VALUES(10002,'1964-06-02','Bezalel','Simmel','F','1985-11-21');
INSERT INTO employees VALUES(10003,'1959-12-03','Parto','Bamford','M','1986-08-28');
INSERT INTO employees VALUES(10004,'1954-05-01','Chirstian','Koblick','M','1986-12-01');
INSERT INTO employees VALUES(10005,'1955-01-21','Kyoichi','Maliniak','M','1989-09-12');
INSERT INTO employees VALUES(10006,'1953-04-20','Anneke','Preusig','F','1989-06-02');
INSERT INTO employees VALUES(10007,'1957-05-23','Tzvetan','Zielinski','F','1989-02-10');
INSERT INTO employees VALUES(10008,'1958-02-19','Saniya','Kalloufi','M','1994-09-15');
INSERT INTO employees VALUES(10009,'1952-04-19','Sumant','Peac','F','1985-02-18');
INSERT INTO employees VALUES(10010,'1963-06-01','Duangkaew','Piveteau','F','1989-08-24');
INSERT INTO employees VALUES(10011,'1953-11-07','Mary','Sluis','F','1990-01-22');
复制
输出：
10005|1955-01-21|Kyoichi|Maliniak|M|1989-09-12

题解

乍一看，很简单，直接用LIMIT：

运行时间：17ms
超过46.54% 用Sqlite提交的代码
占用内存：3404KB
超过53.04%用Sqlite提交的代码

SELECT * FROM employees ORDER BY hire_date DESC LIMIT 2,1;

LIMIT 2,1表示跳过2个数（从第三个数开始取），取值数量为1个。

实际上就正如【牛客SQL】SQL1 查找最晚入职员工的所有信息所说，查找的时候，入职时间排名倒数第三的员工可能不只有一个。因此我们把所有等于排名倒数第三时间的员工所有信息都SELECT出来。

运行时间：16ms
超过56.24% 用Sqlite提交的代码
占用内存：3464KB
超过20.19%用Sqlite提交的代码

SELECT * FROM employees 
WHERE hire_date = (
SELECT hire_date FROM employees ORDER BY hire_date DESC LIMIT 2,1
);