百练 / 2019计算机学科夏令营上机考试 B:打印月历

format函数真的要好好学学，要是不熟悉原本的字符串控制
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# 百练 / 2019计算机学科夏令营上机考试 B:打印月历
# http://bailian.openjudge.cn/xly2019/B/
# Author:NitrogenousFish
# github:https://github.com/NITROGENousFish/
def print_cal(day1is,howmanydays):
    # howmanydays是30,31,28,29
    # day1is取值范围0-6,分别对应下面的内容
    week = ["Sun","Mon","Tue","Wed","Thu","Fri","Sat"]
    dayslist = [str(i+1) for i in range(howmanydays)]

    for _ in range(day1is):
        dayslist.insert(0,"")
    for _ in range(len(dayslist)%7):
        dayslist.append("")
    for i,days in enumerate(week):
        if i!=6:
            print("{:>4}".format(days),end='')
        else:
            print("{:>4}".format(days))
    for iteration in range(len(dayslist)%7+1):
        for i,days in enumerate(dayslist[0+7*iteration:7+7*iteration]):
            if i!=6:
                print("{:>4}".format(days),end='')
            else:
                if iteration == len(dayslist)%7:
                    print("{:>4}".format(days),end='')
                else:
                    print("{:>4}".format(days))

def main():
    # 1900年1月1日是周一
    inputthing = list(map(int,input().split()))
    year, month = inputthing[0],inputthing[1]
    NOT_runian = [31,28,31,30,31,30,31,31,30,31,30,31]
    IS_runian = [31,29,31,30,31,30,31,31,30,31,30,31]
    sumday=0
    for yyy in range(1900,year):
        if not (yyy%4) and yyy%100 and not(yyy%400):
            sumday+=365
        else:
            sumday+=366
    if not (yyy%4) and yyy%100 and not(yyy%400):
        sumday+= sum(IS_runian[0:month])
        returndays = IS_runian[month]
    else:
        sumday+= sum(NOT_runian[0:month])
        returndays = NOT_runian[month]
    return [(sumday+2)%7,returndays]
if __name__ == "__main__":
    out = main()
    print_cal(out[0],out[1])