如何从curl_exec解析结果以提取PHP中的json数据

我收到了包含json数据和其他数据的执行curl_exec的结果。我无法弄清楚如何编辑这个结果。特别是，我需要从结果中包含的json数据编辑一个值。例如，给出以下结果：如何从curl_exec解析结果以提取PHP中的json数据

RESPONSE: HTTP/1.1 400 Bad Request 
Server: nginx 
Date: Sat, 10 Jan 2015 17:31:02 GMT 
Content-Type: application/json 
Content-Length: 25 
Connection: keep-alive 
Keep-Alive: timeout=10 

{"error":"invalid_grant"} 

如何更改“错误”的值？只是使用json_decode本身似乎并不是一个有效的方法。它返回NULL结果：

$obj = json_decode($response); 

建议？

来源

2015-01-10 JeffB6688

A

回答

3

你试过：

curl_setopt($s,CURLOPT_HEADER,false); 

基本上，你正在接收来自服务器的完整响应：

# these are the headers 
RESPONSE: HTTP/1.1 400 Bad Request 
Server: nginx 
Date: Sat, 10 Jan 2015 17:31:02 GMT 
Content-Type: application/json 
Content-Length: 25 
Connection: keep-alive 
Keep-Alive: timeout=10 

# This is the body. 
{"error":"invalid_grant"} 

通过告诉卷曲忽略标题，你应该只得到{"error":"invalid_grant"}

现在，所有这些说，标题分隔两个换行符的身体。所以你应该也可以这样解析：

$val = curl_exec(); 

// list($header,$body) = explode("\n\n", $val); won't work: \n\n is a valid value for 
// body, so we only care about the first instance. 
$header = substr($val, 0, strpos($val, "\n\n")); 
$body = substr($val, strpos($val, "\n\n") + 2); 
// You *could* use list($header,$body) = preg_split("#\n\n#", $val, 2); because that 
// will create an array of two elements. 

// To get the value of *error*, you then 
$msg = json_decode($body); 
$error = $msg->error; 

/* 
The following are because you asked how to "change the value of `error`". 
You can safely ignore if you don't want to put it back together. 
*/ 
// To set the value of the error: 
$msg->error = 'Too many cats!'; 

// to put everything back together: 
$replaced = $header . "\n\n" . json_encode($msg);