array type ‘char [30]‘ is not assignable [duplicate]

转载于 2021-10-15 18:05:18 发布 · 2.2k 阅读

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原文链接：https://stackoverflow.com/questions/63228944/array-type-char-30-is-not-assignable

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本文解析了如何在C语言中正确地为结构体内的字符数组赋值，避免因数组非可修改性导致的错误。通过实例演示了使用strcpy函数代替直接赋值，并解释了原因。

#include <stdio.h>
#include <stdlib.h>

typedef struct node {
  int id;
  int salary;
  struct node *next;
  char name[30];
} List;

int main() {
  List *head = (List *) malloc(sizeof(List)); //allocated memory for head
  if(head == NULL) {
    return 1;
  }

  head -> id = 332513075;
  head -> salary = 100;
  head -> name = "Name Lastname";
  // head -> phone = "0532554891";
  // head -> position = "CEO";
  head -> next = NULL;

  print_list(*head);

  return 0;
}

Error message: array type 'char [30]' is not assignable What is going wrong here and how to fix it?

Arrays are non-modifiable lvalues. That is arrays do not have the assignment operator. You have to copy elements from one array into another.

So instead of this statement

head -> name = "Name Lastname";

write

#include <string.h>

//...

strcpy( head -> name, "Name Lastname" );