hdu 5347 MZL's chemistry 2015多校联合训练赛#5 打表

化学元素电离能比较

最新推荐文章于 2015-08-19 19:36:53 发布

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本文介绍了一种通过原子序数快速比较两种化学元素第一电离能大小的方法，并提供了一个直接输出结果的示例程序。

MZL's chemistry

Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/65536 K (Java/Others)
Total Submission(s): 385 Accepted Submission(s): 314

Problem Description

MZL define

F(X) as the first ionization energy of the chemical element

X

Now he get two chemical elements

U,V ,given as their atomic number,he wants to compare

F(U) and

F(V)

It is guaranteed that atomic numbers belongs to the given set:

{1,2,3,4,..18,35,36,53,54,85,86}

It is guaranteed the two atomic numbers is either in the same period or in the same group

It is guaranteed that

x≠y

Input

There are several test cases

For each test case,there are two numbers

u,v ,means the atomic numbers of the two element

Output

For each test case,if

F(u)>F(v) ,print "FIRST BIGGER",else print"SECOND BIGGER"

Sample Input

  
   1 2
5 3

Sample Output

  
   SECOND BIGGER
FIRST BIGGER

Source

2015 Multi-University Training Contest 5

百度，直接打表输出

#include<iostream>
#include<cstring>
#include<algorithm>
#include<cstdio>
using namespace std;

double res[100]={
0,
1312.0,
2372.3,
520.2,
899.5,
800.6,
1086.5,
1402.3,
1313.9,
1681.0,
2080.7,
495.8,
737.7,
577.5,
786.5,
1011.8,
999.6,
1251.2,
1520.6

};


int main(){
    int n,m;
    res[35] = 1139.9;
    res[36] = 1350.8;
    res[53] = 1008.4;
    res[54] = 1170.4;
    res[85] = 890;
    res[86] = 1037;
    while(cin>>n>>m){
        if(res[n] > res[m]) puts("FIRST BIGGER");
        else puts("SECOND BIGGER");
    }
    return 0;
}