提高篇第28-31课第二题

此程序通过输入字符串,统计其中的字母、数字及元音的数量,并输出每个字母、数字及元音的具体数量。
#include<stdio.h>
#include<stdlib.h>
#include<string.h>
#include<ctype.h>
//第二题
int Count_A(char a[]);
int Count_alpha(char a[]);
int isori(char a);
void Count_every_num(char a[],int b[]);
void Count_every_alpha(char a[],int b[]);
int main()
{
	int CountNum[10] = {0,0,0,0,0,0,0,0,0,0};
	int CountAlpha[255];
	char str[50];
	int countA = 0,countAlpha=0;
	int i = 0, n = 0;
	printf("输入字符串:");
	gets(str);
	while (str[i] != '\0')
	{
		if (str[i] >= '0'&&str[i] <= '9') n++;
		i++;
	}
	for (i = 0; i < 255; i++)
		CountAlpha[i] = 0;
	countA = Count_A(str);
	countAlpha = Count_alpha(str);
	Count_every_alpha(str, CountAlpha);
	Count_every_num(str, CountNum);
	//printf("其中的数字个数是: %d\n", n);
	//Count_every_num(str,Count_num);
	printf("其中字母A的个数是%d\n字母的个数为%d\n", countA,countAlpha);
	printf("其中每个字母的个数为\n");
	for (i = 0; i < 255; i++)
	{
		if (CountAlpha[i] != 0)
		{
			printf("%c有%d个\n", i, CountAlpha[i]);
		}
	}
	printf("其中每个元音字母的个数为\n");
	for (i = 0; i < 255; i++)
	{
		if ((CountAlpha[i] != 0) && (isori(i)==1))
		{
			printf("%c有%d个\n", i, CountAlpha[i]);
		}
	}
	printf("其中每个数字的个数为\n");
	for (i = 0; i < 10; i++)
		printf("%d有%d个\n", i, CountNum[i]);
	return 0;
}
int Count_A(char a[])
{
	int count = 0;
	int i = 0;
	while (a[i] != '\0')
	{
		if (a[i] == 'A')
			count++;
		i++;
	}
	return count;
}
int Count_alpha(char a[])
{
	int count = 0;
	int i = 0;
	while (a[i] != '\0')
	{
		if (isalpha(a[i]))
			count++;
		i++;
	}
	return count;
}
void Count_every_alpha(char a[], int b[])
{
	int i = 0;
	while (a[i] != '\0')
	{
		if (isalpha(a[i]))
			b[a[i]]++;
		i++;
	}
}
int isori(char a)//判断字母是否为元音
{
	int re = 0;
	if (a == 'A' || a == 'a' || a == 'E' || a == 'e' || a == 'I' || a == 'i' || a == 'O' || a == 'o' || a == 'U' || a == 'u')
		re = 1;
	return re;
}
void Count_every_num(char a[],int b[])
{
	int i = 0;
	while (a[i] != '\0')
	{
		if (isdigit(a[i]))
			b[a[i]-48]++;//48为0的ASC码
		i++;
	}
}

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