LeetCode - Dungeon Game

本文介绍了一个迷宫游戏问题,目标是找到骑士救援公主所需的最低初始生命值。文章详细阐述了迷宫布局、骑士行动规则及如何计算最优路径的生命消耗。

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Dungeon Game

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The demons had captured the princess (P) and imprisoned her in the bottom-right corner of a dungeon. The dungeon consists of M x N rooms laid out in a 2D grid. Our valiant knight (K) was initially positioned in the top-left room and must fight his way through the dungeon to rescue the princess.

The knight has an initial health point represented by a positive integer. If at any point his health point drops to 0 or below, he dies immediately.

Some of the rooms are guarded by demons, so the knight loses health (negative integers) upon entering these rooms; other rooms are either empty (0's) or contain magic orbs that increase the knight's health (positive integers).

In order to reach the princess as quickly as possible, the knight decides to move only rightward or downward in each step.


Write a function to determine the knight's minimum initial health so that he is able to rescue the princess.

For example, given the dungeon below, the initial health of the knight must be at least 7 if he follows the optimal path RIGHT-> RIGHT -> DOWN -> DOWN.

-2 (K) -3 3
-5 -10 1
10 30 -5 (P)

Notes:

  • The knight's health has no upper bound.
  • Any room can contain threats or power-ups, even the first room the knight enters and the bottom-right room where the princess is imprisoned.






倒着走比较好做,从右下角往左上角推每一格的最小初始体力


class Solution {
public:
    int calculateMinimumHP(vector<vector<int>>& dungeon) {
        int n, m;
        if((n = dungeon.size()) == 0 || (m = dungeon[0].size()) == 0) 
            return 0;
        f = vector<vector<int> > (n, vector<int> (m, 0));
        f[n - 1][m - 1] = max(0, 0 - dungeon[n - 1][m - 1]);
        for(int i = m - 2; i >= 0; --i){
            f[n - 1][i] = max(f[n - 1][i + 1] - dungeon[n - 1][i], 0);
        }
        for(int i = n - 2; i >= 0; --i){
            f[i][m - 1] = max(f[i + 1][m - 1] - dungeon[i][m - 1], 0);
        }
        for(int i = n - 2; i >= 0; --i)
        for(int j = m - 2; j >= 0; --j){
            f[i][j] = max(min(f[i + 1][j], f[i][j + 1]) - dungeon[i][j], 0);
        }
        return f[0][0] + 1;
        
    }
private:
    vector<vector<int> > f;
};


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