链表问题

Palm os 程序设计课程设计题目

设计一个学生成绩表,数据库包含:学生姓名(name), 成绩(mark)


并且在文档中写明设计思路,流程,以及各个函数的作用


用C语言写,要求就这么简单

要去吃饭了,编译错误都解决了,还剩下一个连接错误.
吃完了再帮你解决(最好你自己去搞顶).
思路在注释里面很清楚了,自己拿出来就可以把文档完成.
这靠你自己去搞.



#include <stdio.h>
#include <malloc.h>
#include <string.h>
#define NULL 0             //定义NULL宏
#define LEN sizeof(struct student)     //定义LEN宏,替代struct student类型的长度

struct student           //声明了struct student的类型
{
    char name[15];       //学生姓名
    float score;         //学生成绩
    struct student *next;    //定义的指向下一个学生的指针
};

/*********一般的建个学生链表有以下几个函数就应该可以了*********/
struct student *creat(void);          //创建 一个学生链表,返回一个指向链表头的指针  
void print(struct student *head);     //打印出学生链表
struct student *del(struct student *head,char name[]);     //删除名称为name的学生
struct student *insert(struct student *head, struct student *stud);  //插入新的学生信息

int n;         //n为全局变量,对表中结点的个数进行掌控

struct student *create(void)
{
    struct student *head;
    struct student *p1,*p2;
    n = 0;
    p1 = p2 = (struct student*)malloc(LEN); //开辟的第一个单元,并却强制转换其类型
    scanf("%s,%f",&p1->name,&p1->score);
    head = NULL;
    while(p1 ->name != 0)
    {
        n = n+1;
        if(n == 1)
            head = p1;
        else
            p2->next = p1;
            p1 = p2;
            p1 = (struct student*)malloc(LEN);
            scanf("%s,%f",&p1->name,&p1->score);
    }
    p2->next = NULL;
    return(head);
}


void print(struct student *head)
{
    struct student *p;
    printf("now ,these %d records are:/n",n);
    p = head;
    if(head != NULL)
        do
        {
            printf("%s,%f/n",p->name,p->score);
            p = p->next;
        }while(p != NULL);
}

struct student *del(struct student *head,char name[])
{
    struct student *p1,*p2;
    if(head == NULL)
    {
        printf("/n list null!");
    }
    p1 = head;
    while(strcmp(name,p1->name) != 0 && p1->next != NULL)
        //p1指向的不是所要的结点,却后面还有结点
    {
        p2 = p1;
        p1 = p1->next;
    }
    if(strcmp(name,p1->name) == 0)     //找到了
    {
        if(p1 == head)
            head = p1->next;
        else
            p2->next = p1->next;
        printf("delete:%s/n",name);
        n = n-1;
    }
    else printf("can not been found!");
    return head;
}

struct student *insert(struct student *head,struct student *stud)
{
    struct student *p0, *p1, *p2;
    p1 = head;
    p0 = stud;
    if(head == NULL)
    {
        head = p0;
        p0->next = NULL;
    }
    else
    {
        while(strcmp(p0->name,p1->name) > 0&&(p1->next != NULL))
        {
            p2 = p1;
            p1 = p1->next;
        }
        if(strcmp(p0->name,p1->name)<0)
        {
            if(head == p1)
                head = p0;
            else
                p2 ->next = p0;
            p0->next = p1;
        }
        else
        {
            p1->next = p0;
            p0->next =NULL;
        }
    }
    n = n+1;
    return(head);
}

void main()
{
    struct student *head,stu;
    char name[20];
    printf("input records:/n");
    head = creat();
    print(head);
    printf("/ninput the deleted number:");
    scanf("%s",name);
    head = del(head,name);
    print(head);
    printf("/ninput the insert records:");
    scanf("%s,%f",&stu.name,&stu.score);
    head = insert(head,&stu);
    print(head);
}

 
评论
添加红包

请填写红包祝福语或标题

红包个数最小为10个

红包金额最低5元

当前余额3.43前往充值 >
需支付:10.00
成就一亿技术人!
领取后你会自动成为博主和红包主的粉丝 规则
hope_wisdom
发出的红包
实付
使用余额支付
点击重新获取
扫码支付
钱包余额 0

抵扣说明:

1.余额是钱包充值的虚拟货币,按照1:1的比例进行支付金额的抵扣。
2.余额无法直接购买下载,可以购买VIP、付费专栏及课程。

余额充值