Broken Necklace

最新推荐文章于 2018-11-30 23:43:33 发布

fjiajun

最新推荐文章于 2018-11-30 23:43:33 发布

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分类专栏： USACO 文章标签： usaco c

本文链接：https://blog.youkuaiyun.com/fengjiajun169/article/details/28633765

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该程序使用C语言计算从1899年12月31日到指定日期之间的天数，并根据天数计算出每周中每一天的数量，最终将结果输出到文件中。

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/*
ID: mrster.1
LANG: C
TASK: friday
*/

#include <stdio.h>
#include <stdlib.h>

int main()
{
    int n = 0;
    int countDays = 0;
    int week[7];
    int i = 0,j;
    FILE *fin = fopen("friday.in","r");
    FILE *fout = fopen("friday.out","w");
    for(i = 0;i<7;i++)
    {
        week[i] = 0;
    }
    fscanf(fin,"%d",&n);
    countDays = countDay(1899+n,12,31);
    for(i = 1;i<=n;i++)
    {
        for(j = 1;j<=12;j++)
        {
            countDays = countDay(1899+i,j,13);
            week[(countDays-1)%7]++;
        }
    }
    fprintf(fout,"%d %d ",week[5],week[6]);
    for(i = 0;i<5;i++)
    {
        if(i!=4)fprintf(fout,"%d ",week[i]);
        else fprintf(fout,"%d",week[i]);
    }
    fprintf(fout,"\n");
}

int countDay(int year,int month,int day)
{
    int countDay = 0;
    int i = 0;
    for(i = 1900;i<year;i++)
    {
        if(isLeapYear(i)==1)countDay += 366;
        else countDay +=365;
    }
    countDay +=countCurrentDay(year,month,day);
    return countDay;
}

int countCurrentDay(int year,int month,int day)
{
    int countDay = 0;
    int flag = 0;
    flag = isLeapYear(year);
    switch(month-1)
    {
        case 11 :countDay+=30;
        case 10 :countDay+=31;
        case 9 :countDay+=30;
        case 8 :countDay+=31;
        case 7 :countDay+=31;
        case 6 :countDay+=30;
        case 5 :countDay+=31;
        case 4 :countDay+=30;
        case 3 :countDay+=31;
        case 2 :countDay+=28+flag;
        case 1 :countDay+=31;
        break;
    }
    countDay +=day;
    return countDay;
}

int isLeapYear(int year)
{
    int flag = 0;
    if(year%100!=0)
    {
        if(year%4==0)flag = 1;
    }
    else if(year%100==0)
    {
        if(year%400==0)flag = 1;
    }
    return flag;
}