简单枚举类型——植物与颜色

植物颜色匹配程序

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本程序通过定义枚举类型color来匹配六种特定颜色与相应植物的关联，接收颜色名称输入并输出对应植物的颜色，对于未定义的颜色则给出提示。

简单枚举类型——植物与颜色

Time Limit: 1000MS Memory Limit: 65536KB

Submit Statistic

Problem Description

请定义具有red, orange, yellow, green, blue, violet六种颜色的枚举类型color，根据输入的颜色名称，输出以下六种植物花朵的颜色：

Rose(red), Poppies(orange), Sunflower(yellow), Grass(green), Bluebells(blue), Violets(violet)。如果输入的颜色名称不在枚举类型color中，例如输入purple，请输出I don't know about the color purple.

Input

输入数据有多行，每行有一个字符串代表颜色名称，颜色名称最多30个字符，直到文件结束为止。

Output

输出对应颜色的植物名称，例如：Bluebells are blue. 如果输入的颜色名称不在枚举类型color中，例如purple, 请输出I don't know about the color purple.

Example Input

blue
yellow
purple

Example Output

Bluebells are blue.
Sunflower are yellow.
I don't know about the color purple.

Hint

请用枚举类型实现。

#include <stdio.h>  
#include <string.h>  
int main()  
{  
    char str[20];  
    enum color{red,orange,yellow,green,blue,violet};  
    while (gets(str)!=NULL)  
    {  
        if(strcmp(str,"red")==0)  
            printf("Rose are red.\n");  
        else if(strcmp(str,"orange")==0)  
            printf("Poppies are orange.\n");  
        else if(strcmp(str,"yellow")==0)  
            printf("Sunflower are yellow.\n");  
        else if(strcmp(str,"green")==0)  
            printf("Grass are green.\n");  
        else if(strcmp(str,"blue")==0)  
            printf("Bluebells are blue.\n");  
        else if(strcmp(str,"violet")==0)  
            printf("Violets are violet.\n");  
        else  
            printf("I don't know about the color %s.\n",str);  
  
    }  
    return 0;  
} 

/***************************************************
User name: zxw140231刘真真
Result: Accepted
Take time: 0ms
Take Memory: 108KB
Submit time: 2017-01-11 11:08:29
****************************************************/