Longest Valid Parentheses Hard
Given a string containing just the characters '(' and ')', find the length of the longest valid (well-formed) parentheses substring.
For "(()", the longest valid parentheses substring is "()", which has length = 2.
Another example is ")()())", where the longest valid parentheses substring is "()()", which has length = 4.
public int longestValidParentheses(String s) {
Stack<Integer> stack = new Stack<Integer>();
int max = 0;
int left = -1;
for (int j = 0; j < s.length(); j++) {
if (s.charAt(j) == '(')
stack.push(j);
else {
if (stack.isEmpty())
left = j;
else {
stack.pop();
if (stack.isEmpty())
max = Math.max(max, j - left);
else
max = Math.max(max, j - stack.peek());
}
}
}
return max;
}
思路:典型压栈题目。遇左括号压栈,右括号判断是否合法,合法弹出判定最大长度,不合法则把左边界右移。特殊情况:栈不为空时也有可能取得最大长度。
本文介绍了一种解决寻找最长有效括号子串问题的高效算法,通过使用栈来跟踪左括号的位置,遇到右括号时检查是否形成有效的括号对,以此更新最长有效括号子串的长度。
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