3Sum Medium
Given an array S of n integers, are there elements a, b, c in S such that a + b + c = 0? Find all unique triplets in the array which gives the sum of zero.
Note: The solution set must not contain duplicate triplets.
For example, given array S = [-1, 0, 1, 2, -1, -4],
A solution set is:
[ [-1, 0, 1],
[-1, -1, 2]]
public List<List<Integer>> threeSum(int[] nums) { List<List<Integer>> result = new ArrayList<>(); if (nums.length < 3) return result; Arrays.sort(nums); int i = 0; while (i < nums.length - 2) { if (nums[i] > 0) break; int j = i + 1; int k = nums.length - 1; while (j < k) { int sum = nums[i] + nums[j] + nums[k]; if (sum == 0) result.add(Arrays.asList(nums[i], nums[j], nums[k])); if (sum <= 0) while (nums[j] == nums[++j] && j < k) ; if (sum >= 0) while (nums[k--] == nums[k] && j < k) ; } while (nums[i] == nums[++i] && i < nums.length - 2) ; } return result; }
思路1:先排序O(nlogn),然后查每一个数后面两数之和为当前数相反数的所有可能(夹逼法)。O(n2)
思路2(未实现):不排序,先做2数和的倒排索引,查每一个数是否有相应的2数和为其相反数。O(n3)
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