fbysss的专栏

$_SERVER[“HTTP_REFERER“]可以得到是有哪个页面提交的请求。$url = $_SERVER[SERVER_NAME].$_SERVER[PHP_SELF];$url_full= $url.?.$_SERVER[QUERY_STRING];//得到当前的url读取页面参数：$username= $_GET["username"]; 如果是POST则用$userna

作者:snowai 来源:PHPX.com <!--google_ad_client = "pub-2928087963304701";google_ad_width = 468;google_ad_height = 60;google_ad_format = "468x60_as";google_ad_channel ="9725746080";google_c