指针隐式转换-微软实习笔试题

#include <iostream>
using namespace std;



class A
{
public:
	long a;
};

class B:public A
{
public:
	long b;
};

void seta(A *p, int i)
{
	p[i].a=2;
}


int main()
{
	B bb[4];
	int i;
	for(i=0; i<4; i++)
	{
		bb[i].a=1;
		bb[i].b=1;
		seta(bb,i);
	}
	for (i=0; i<4; i++)
	{
		cout<<bb[i].a<<bb[i].b;
	}
	cout<<endl;
	return 0;
}

 

但是选项里没有这个答案额！