https://blog.youkuaiyun.com/everything_studyzh-cnhttps://blog.youkuaiyun.com/https://blog.youkuaiyun.com/everything_study/article/details/152177434https://blog.youkuaiyun.com/everything_study/article/details/152177434everything_studySat, 27 Sep 2025 20:46:12 +0800https://blog.youkuaiyun.com/everything_study/article/details/151720001https://blog.youkuaiyun.com/everything_study/article/details/151720001everything_studyMon, 15 Sep 2025 16:01:01 +0800https://blog.youkuaiyun.com/everything_study/article/details/151653741https://blog.youkuaiyun.com/everything_study/article/details/151653741everything_studySat, 13 Sep 2025 16:30:20 +0800https://blog.youkuaiyun.com/everything_study/article/details/151652772https://blog.youkuaiyun.com/everything_study/article/details/151652772everything_studySat, 13 Sep 2025 15:59:01 +0800https://blog.youkuaiyun.com/everything_study/article/details/151647355https://blog.youkuaiyun.com/everything_study/article/details/151647355everything_studySat, 13 Sep 2025 10:58:33 +0800https://blog.youkuaiyun.com/everything_study/article/details/151647263https://blog.youkuaiyun.com/everything_study/article/details/151647263everything_studySat, 13 Sep 2025 10:56:35 +0800https://blog.youkuaiyun.com/everything_study/article/details/151647204https://blog.youkuaiyun.com/everything_study/article/details/151647204everything_studySat, 13 Sep 2025 10:55:11 +0800https://blog.youkuaiyun.com/everything_study/article/details/151017625https://blog.youkuaiyun.com/everything_study/article/details/151017625everything_studySat, 30 Aug 2025 13:41:25 +08000:return 1else:return 0AND(1,1),AND(0,1),AND(1,0))]]>https://blog.youkuaiyun.com/everything_study/article/details/150608201https://blog.youkuaiyun.com/everything_study/article/details/150608201everything_studyFri, 22 Aug 2025 12:57:36 +0800https://blog.youkuaiyun.com/everything_study/article/details/150607872https://blog.youkuaiyun.com/everything_study/article/details/150607872everything_studyFri, 22 Aug 2025 12:25:34 +0800nums[middle+2]将middle处的元素与middle+1的位置元素进行相比，如果nums[middle]https://blog.youkuaiyun.com/everything_study/article/details/150588634https://blog.youkuaiyun.com/everything_study/article/details/150588634everything_studyThu, 21 Aug 2025 18:03:56 +0800https://blog.youkuaiyun.com/everything_study/article/details/150551012https://blog.youkuaiyun.com/everything_study/article/details/150551012everything_studyWed, 20 Aug 2025 12:09:19 +0800https://blog.youkuaiyun.com/everything_study/article/details/150548897https://blog.youkuaiyun.com/everything_study/article/details/150548897everything_studyWed, 20 Aug 2025 10:59:58 +0800https://blog.youkuaiyun.com/everything_study/article/details/150468144https://blog.youkuaiyun.com/everything_study/article/details/150468144everything_studySun, 17 Aug 2025 15:39:06 +0800https://blog.youkuaiyun.com/everything_study/article/details/150465296https://blog.youkuaiyun.com/everything_study/article/details/150465296everything_studySun, 17 Aug 2025 12:07:37 +0800https://blog.youkuaiyun.com/everything_study/article/details/150443974https://blog.youkuaiyun.com/everything_study/article/details/150443974everything_studySat, 16 Aug 2025 11:52:07 +0800https://blog.youkuaiyun.com/everything_study/article/details/150421445https://blog.youkuaiyun.com/everything_study/article/details/150421445everything_studyFri, 15 Aug 2025 14:00:36 +0800https://blog.youkuaiyun.com/everything_study/article/details/150419297https://blog.youkuaiyun.com/everything_study/article/details/150419297everything_studyFri, 15 Aug 2025 11:45:18 +0800https://blog.youkuaiyun.com/everything_study/article/details/150276469https://blog.youkuaiyun.com/everything_study/article/details/150276469everything_studyTue, 12 Aug 2025 17:04:08 +0800https://blog.youkuaiyun.com/everything_study/article/details/150220490https://blog.youkuaiyun.com/everything_study/article/details/150220490everything_studyMon, 11 Aug 2025 17:16:05 +0800=k的时候，这个珂珂就能够顺利吃掉所有的香蕉，而我们知道二分查找算法可以找到满足条件最小一个数，即>=k。确定这个二分查找算法的边界（使用左开右开，这样方便，不用对这个right和left的最后结果做判断了）此时我们需要遍历这个堆，然后计算此时的次数，这个地方涉及了一个整数向上取整。这个条件就是当我们使用这个k速度吃香蕉的时候，能否吃完。在二分查找的时候我们要判断当前的数是否满足条件。这个条件就是当速度为k的时候可以吃完这些香蕉。]]>