<?xml version="1.0" encoding="utf-8" ?><rss version="2.0"><channel><title><![CDATA[etranger的博客]]></title><description><![CDATA[]]></description><link>https://blog.youkuaiyun.com/etranger</link><language>zh-cn</language><generator>https://blog.youkuaiyun.com/</generator><copyright><![CDATA[Copyright &copy; etranger]]></copyright><item><title><![CDATA[计算全球震相的程序]]></title><link>https://blog.youkuaiyun.com/etranger/article/details/146983537</link><guid>https://blog.youkuaiyun.com/etranger/article/details/146983537</guid><author>etranger</author><pubDate>Thu, 03 Apr 2025 16:59:43 +0800</pubDate><description><![CDATA[int N = 50;// 需要根据实际需求设置。]]></description><category></category></item><item><title><![CDATA[matlab代码的BBP算法，中间出现最大数为base*bits]]></title><link>https://blog.youkuaiyun.com/etranger/article/details/144848027</link><guid>https://blog.youkuaiyun.com/etranger/article/details/144848027</guid><author>etranger</author><pubDate>Tue, 31 Dec 2024 13:22:23 +0800</pubDate><description><![CDATA[可计算到万亿位pi的16进制，用6个公式相互比较，保证不出错。
位数位正数，输出有限个，位数位负数，全部输出]]></description><category></category></item><item><title><![CDATA[为什么huvent8项公式用取整法求PI的16进制第4项出错]]></title><link>https://blog.youkuaiyun.com/etranger/article/details/144740728</link><guid>https://blog.youkuaiyun.com/etranger/article/details/144740728</guid><author>etranger</author><pubDate>Thu, 26 Dec 2024 12:38:29 +0800</pubDate><description><![CDATA[result = hex(totalSum>>(N-1)*M*4)[2:]  # 去掉 '0x' 前缀。]]></description><category></category></item><item><title><![CDATA[生成PI任意位数]]></title><link>https://blog.youkuaiyun.com/etranger/article/details/144678417</link><guid>https://blog.youkuaiyun.com/etranger/article/details/144678417</guid><author>etranger</author><pubDate>Mon, 23 Dec 2024 21:43:41 +0800</pubDate><description><![CDATA[include <gmp.h>  // GMP 的 C 接口头文件（可选，但通常包含以获取 GMP 定义的常量）#include <gmpxx.h> // GMP 的 C++ 接口头文件。]]></description><category></category></item><item><title><![CDATA[SPP利用折射率剖面进行GPS定位]]></title><link>https://blog.youkuaiyun.com/etranger/article/details/137274826</link><guid>https://blog.youkuaiyun.com/etranger/article/details/137274826</guid><author>etranger</author><pubDate>Tue, 02 Apr 2024 16:27:35 +0800</pubDate><description><![CDATA[运行CRinex.exe，目前支持Rinex2.2格式，打开.o文件，导入.n文件，可以选择C1。P1,P2频道进行定位处理，获得平均位置+钟差和数据方差。]]></description><category></category></item><item><title><![CDATA[仅有唯一答案的算24点题目]]></title><link>https://blog.youkuaiyun.com/etranger/article/details/127108356</link><guid>https://blog.youkuaiyun.com/etranger/article/details/127108356</guid><author>etranger</author><pubDate>Thu, 29 Sep 2022 15:49:59 +0800</pubDate><description><![CDATA[有一些比较容易，有一些则较难，要考虑大数算法或分数算法]]></description><category></category></item><item><title><![CDATA[算24的所有可能，考虑交换律等冗余]]></title><link>https://blog.youkuaiyun.com/etranger/article/details/126887387</link><guid>https://blog.youkuaiyun.com/etranger/article/details/126887387</guid><author>etranger</author><pubDate>Fri, 16 Sep 2022 11:40:38 +0800</pubDate><description><![CDATA[要求输入数据个数，然后输入每个数。如果数据个数为正，只考虑加减乘除。如果数据个数为负数则考虑加减乘除乘方除方与或左移右移等二元操作。通过第一层递归获取N-N-1个数的任意排列（前N个为数据，后N-1个为操作符），并判断是否符合逆波兰表达式，如果符合进行第二层递归考虑所有操作符的组合，然后进行逆波兰计算结果如果等于要求则打印结果。]]></description><category></category></item></channel></rss>