zoj1048体会

针对刚毕业工作的Larry遇到的财务管理难题,本篇介绍了一个简单的C语言程序,该程序能够帮助计算过去十二个月银行账户的平均余额,从而为解决他的财务困扰提供支持。

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Financial Management

Larry graduated this year and finally has a job. He's making a lot of money, but somehow never seems to have enough. Larry has decided that he needs to grab hold of his financial portfolio and solve his financing problems. The first step is to figure out what's been going on with his money. Larry has his bank account statements and wants to see how much money he has. Help Larry by writing a program to take his closing balance from each of the past twelve months and calculate his average account balance.


Input Format:

The input will be twelve lines. Each line will contain the closing balance of his bank account for a particular month. Each number will be positive and displayed to the penny. No dollar sign will be included.


Output Format:

The output will be a single number, the average (mean) of the closing balances for the twelve months. It will be rounded to the nearest penny, preceded immediately by a dollar sign, and followed by the end-of-line. There will be no other spaces or characters in the output.

Sample Input:

100.00
489.12
12454.12
1234.10
823.05
109.20
5.27
1542.25
839.18
83.99
1295.01
1.75


Sample Output:

$1581.42

 

我第一次的代码:

#include<stdio.h>

void main()
{
 float d,sum,average;
 int i;

while(1)
    sum=0;
    for(i=0;i<12;i++)
    {
     scanf("%f",&d);
     sum+=d;
    }
    average=sum/12;
    printf("$%.2f/n",average);

}
}

结果TLE,不能ac;这是因为我原来做hdu的题目,习惯了多个测试案例,本题目的意思是只有一个测试用例,不需要while循环;

去掉while循环后,语言选择C(gcc4.4.5),提交后出现non-zero exit code;语言选择C++(g++4.4.5)提交后是编译错误,原因是main必须return,改成如下代码后则可以ac。

#include<stdio.h>

int main()
{
 float d,sum,average;
 int i;
    sum=0;
    for(i=0;i<12;i++)
    {
     scanf("%f",&d);
     sum+=d;
    }
    average=sum/12;
    printf("$%.2f/n",average);
    return 0;
}

总结如下,在zoj上做题时要看清题意,用C或C++main必须有return

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