两道题都是思路简单,但是代码两眼一抹黑,多多背多多练
129 Sum Root to Leaf Numbers【默写】
/**
* Definition for a binary tree node.
* struct TreeNode {
* int val;
* TreeNode *left;
* TreeNode *right;
* TreeNode() : val(0), left(nullptr), right(nullptr) {}
* TreeNode(int x) : val(x), left(nullptr), right(nullptr) {}
* TreeNode(int x, TreeNode *left, TreeNode *right) : val(x), left(left), right(right) {}
* };
*/
class Solution {
public:
int dfs(TreeNode* node , int currentSum){
if(!node) return 0;
currentSum = currentSum*10 + node->val;
if(!node->left && !node->right){
return currentSum