题目地址:http://pat.zju.edu.cn/contests/pat-a-practise/1005
对于大数N (<= 10^100)的处理,考虑使用字符串。
代码如下:
#include<map>
#include<string>
#include<iostream>
#include<vector>
#include<string.h>
#include<algorithm>
#include<stdlib.h>
#include<stdio.h>
#include<set>
using namespace std;
int main()
{
string numE[10]={"zero","one","two","three","four","five","six","seven","eight","nine"};
int i;
map<char,int>m;
for(i=0;i<=9;i++)
m['0'+i]=i;
string str;
cin>>str;
int sum=0;
for(i=0;i<str.length();i++)
sum+=m[str[i]];
char c[10000];
string strSum;
sprintf(c,"%d",sum);
strSum=c;
for(i=0;i<strSum.length();i++){
int temp=strSum[i]-48;
if(i!=strSum.length()-1)
cout<<numE[temp]<<" ";
else
cout<<numE[temp]<<endl;
}
return 0;
}