11_5_2扩展上一题中的Person 类，重载>、<、>=和<=运算符，比较Person实例的Age属性

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原创最新推荐文章于 2026-08-27 17:08:04 发布 1k 阅读 AI 写同款· GEO 优化 ›

C++字典序比较：从std::lexicographical_compare到关联容器与C++20三路比较字典序比较是计算机科学中处理序列排序的基础概念，其核心原理是逐元素比较，首差异定胜负。在C++标准库中，这一概念通过多种技术载体实现，为数据组织和算法提供了统一的比较框架。其技术价值在于为关联容器（如std::map、std::set）提供了严格的弱序基础，确保了元素查找、插入的高效性与正确性，同时也是通用算法（如排序、查找）和自定义类型比较的基石。应用场景广泛，包括字符串排序、自定义数据结构比较、数据库索引模拟等。本文聚焦于C++标准库中字典序比较的综合实现，深入剖析了`std::lexicographi 阅读详情

//file Person.cs
using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;

namespace _11_5_1
{
    class Person
    {
        private string name;
        private int age;

        public string Name
        {
            get
            {
                return name;
            }
            set
            {
                name = value ;   
            }
        }

        public int Age
        {
            get 
            {
                return age;
            }
            set
            {
                age = value;
            }
        }

        public Person()
        { }

        public Person(string name, int age)
        {
            this.name = name;
            this.age = age;
        }

        public static bool operator > (Person per1,Person per2)
        {
            return (per1.Age>per2.Age);
        }

        public static bool operator<(Person per1,Person per2)
        {
            return (per1.Age < per2.Age);
        }

        public static bool operator <=(Person per1, Person per2)
        {
            return (per1.Age <= per2.Age);
        }

        public static bool operator >=(Person per1,Person per2)
        {
            return (per1.Age >= per2.Age);
        }
    }
}


//------------------------------------------

//file Program.cs
using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;

namespace _11_5_1
{
    class Program
    {
        static void Main(string[] args)
        {
            People people = new People();

            Person per1 = new Person("Chuck", 24);
            Person per2 = new Person("Candy", 30);

            people.Add("Chuck", per1);
            people.Add("Candy", per2);

            Console.WriteLine("{0} {1}",
                people["Chuck"].Name, people["Chuck"].Age);
            Console.WriteLine("{0} {1}",
                people["Candy"].Name, people["Candy"].Age);

            //-----------------------------------------------

            if (per1 > per2)
            {
                Console.WriteLine("per1 > per2 of Age");
            }
            if (per1 <= per2)
            {
                Console.WriteLine("per1 <= per2 of Age");
            }
            
        }
    }
}

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